How to find the antiderivative of $\\sqrt{25-x^2}$? How would I do it? Integration by substitution doesn't seem to work in this case.

Dec 9, 2020 · Using trigonometric substitution to integrate $\int\frac {x^3dx} {\sqrt {25-x^2}}$ Ask Question Asked 4 years, 11 months ago Modified 4 years, 11 months ago

Jul 23, 2020 · Partial Fraction Decomposition of $\frac {1} {x^2 (x^2+25)}$ Ask Question Asked 5 years, 4 months ago Modified 5 years, 4 months ago

Mar 26, 2011 · There is a basic approach here, called "trigonometric substitution." This is something to use whenever you have an integral that contains a radical of any of the following forms: $$\sqrt {a^2 …

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Dec 26, 2018 · The question is to find a vector equation for the tangent line to the curve of intersection of the cylinders $x^2+y^2=25$ and $y^2+z^2=20$ at the point $ (3,4,2)$.

Jul 29, 2018 · 5 I recognize the two difference of squares: $49-x^2$ and $25-x^2$. I squared the equation to get: $ {49-x^2}-2 (\sqrt { (49-x^2) (25-x^2)})+ {25-x^2}=9$ However, I can't quite figure out …

Nov 8, 2018 · EDIT: A Late Addressing of OP's Actual Question: (No clue why I - or anyone outside the comments - never thought to actually do this years ago, but whatever.) OP's confusion lies in …

Jan 28, 2019 · This is what I did: I try to multiply by the conjugate. Its value I believe is technically the solution. $ (\sqrt {49-x^2} + \sqrt {25-x^2}) (\sqrt {49-x^2} - \sqrt ...

Oct 16, 2021 · If you do $\require {cancel}x=5\tan\theta$ and $\mathrm dx=5\sec^2\theta\,\mathrm d\theta$, then $\int\frac1 {\sqrt {25+x^2}}\,\mathrm dx$ becomes $$\int\frac ...