This simulation demonstrates the working of a Boost Converter circuit. A 5V DC input is applied, and through the combination of an inductor L1 (1H), diode D1, switching transistor Q2, and capacitor C1 (10µF), the circuit steps up the voltage to approximately 12V at the output. The graph shows the PWM signal (orange) controlling the transistor and the resulting boosted output voltage (blue) gradually increasing above the input level. #boostconverter #CircuitSimulation #powerelectronics #Electroni

How a Boost Converter circuit works | DC to DC step up voltage | How to increase DC Voltage

This Simulation illustrates the working of a Boost Converter, which steps up a DC input voltage to a higher DC output. The input is 5 V, and through the switching action of a transistor (driven at 1 kHz), energy is stored in a 100 mH inductor and then released through a diode into a 10 µF capacitor. The result is a boosted output voltage of around 10 V across a 1 kΩ load. The waveform shows the switching signal (orange) and the rising output voltage (blue), clearly demonstrating voltage boosting